Math, asked by palak2059, 8 months ago

if a and b are zeroes of 3x^2-2x-6 then value of 1/a +1/b is?

Answers

Answered by abhi569
1

Answer:

-1/3

Step-by-step explanation:

→ 3x² - 2x - 6 → 3(x² - 2x/3 - 2)

Polynomials written in form of k(x² - Sx + P), represent S as sum of their roots and P as product of roots.

So, here, if a and b are roots:

• a + b = 2/3

• ab = - 2

So,

= > 1/a + 1/b

= > (b + a)/ab

= > (2/3)/(-2)

= > -1/3

Answered by Rudranil420
53

Answer:

⭐ Given ⭐

✍ If a & b are the zeroes of 3x²-2x-6

⭐ To find ⭐

✍ 1/a + 1/ b

⭐ Solution ⭐

=> 3x²-2x-6

=> 3(x²-2x/3-2)

➡ Polynomial can be written as

✍ k(x² - SX + P)

Where,

⚫ S = Sum of the roots.

⚫ P = Product of the roots.

⭕ So here, α and β are the roots,

✏ a+b = 2/3

✏ a×b = -2

➡ Now,

=> 1/a + 1/b

=> (b+a)/a×b( putting the value of a+b = 2/3 and a×b = -2)

=> (2/3)/(-2)

=> -1/3✔

The value of 1/a +1/b = -1/3

Step-by-step explanation:

HOPE IT HELP YOU

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