if a and b are zeroes of polynomial p(x) = 3xsq - 4x - 7 then form a quadratic polynomial whose zeroes are 1/a and 1/b
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Answer:
7x^2+4x-3=0
Step-by-step explanation:
3x^2-4x-7=0
3x^2-7x+3x-7=0
x(3x-7)+1(3x-7)=0
(x+1)(3x-7)=0
roots -1 and 7/3
1/a =-1
1/b=3/7
x^2-(sum of roots)x + (product of roots)=0
x^2-(-1+3/7)x+(-1*3/7)=0
x^2+(4/7)x-3/7=0
7x^2+4x-3=0
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