If a and b are zeroes of polynomial x²-6x+k and 3a +2b = 20 then value of k is
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Answer:
Answer - 20
Step-by-step explanation:
x^2 - 6x + k =0
sum of roots a+b= 6-------------------(I)
product a b= k----------------(II)
and 3a+ 2b = 20---------------(III)
b= -2
a= 8
so k = ab = -16 answer
proof--------------
x^2 - 6x - 16 =0
( x- 8) ( x +2) =0
so x= 8 & x= -2
3a+ 2b= 24- 2 = 20
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