If a and b are zeroes of the polynomial x^2-x -6, find a quadratic polynomial whose zeroes are (3a+2b) and (2a+3b)
Answers
Answered by
3
As we know quadratic equation have only two solutions
Therefore,
p(x)=(3a+2b)(2a+3b)
=6a^2+9ab+4ab+6b^2
=6a^2+13ab+6b^2
Therefore,
p(x)=(3a+2b)(2a+3b)
=6a^2+9ab+4ab+6b^2
=6a^2+13ab+6b^2
Similar questions
Biology,
7 months ago
Math,
7 months ago
Science,
1 year ago
Political Science,
1 year ago
Chemistry,
1 year ago