if a and b are zeroes of the polynomial x2-p(x-1)+c such that (a+1)(b+1)=0 then find the value of c
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Answer:
c=p(1-x)-1
Step-by-step explanation:
(a+1)(b+1)=0
ab+(a+b)+1=0
c+p(x-1)+1=0
c=p(1-x)-1
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