if a and b are zeroes of the polynomial x2-x-6, then find the quadratic polynomial of (2a+3b) abd (3a+2b)
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Answer:
0 and 5.
Step-by-step explanation:
x^2-x-6
=> x^2-3x+2x-6=0
=> x(x-3)+2(x-3)=0
=> (x-3)(x+2)=0
=> x=3 or x=-2
Let us consider a=3 and b=-2
Now, (2a+3b) = 6+(-6) = 0.
Also, (3a+2b) = 9+2(-2) = 5.
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