Question

if a and b are zeroes of the quadric polynomial f( x) =6x^2+x-2 find value of a/b+b/a​

Answer 1

f(x) = 6x ^ 2 - x - 2 Since a and ẞ are the zeroes of the given polynomial .. Sum of zeroes [alpha + beta] = - 1/6 Product of zeroes (alpha*beta) = - 1/3; = alpha beta + beta alpha = alpha^ 2 + beta^ 2 alpha beta = ( alpha+ beta)^ 2 -2 alpha beta alpha beta; = ( 1 6 )^ 2 -2*( -1 3 ) 1 3 = 1 6 - 2 3 -1 3 = 1+24 36 -1 3; = 2 36 1 3 = -25 12