if a and b are zeroes of the quadric polynomial f( x) =6x^2+x-2 find value of a/b+b/a
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Given that,
α and β are the zeroes of the quadratic polynomial f(x) = 6x2 + x – 2.
therefore,
Sum of the zeroes = α + β = -1/6,
Product of the zeroes =α × β = -1/3.
Now,
(α/β) +(β/α) = (α2 + β2) – 2αβ / αβ
Now substitute the values of the sum of zeroes and products of the zeroes and we will get,
= -25/12
Hence the value of (α/β) +(β/α) is -25/12
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