Question

If a and B are zeros of p(x)=4x^2 -5x -1 , then the value of aB^2 + Ba^2 is :-

anyone plz get the answer of this question
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Answer 1

Answer:

4x^2-5x-1

Step-by-step explanation:

sum of zeroes= -b/a

=-(-5)/4

sum =5/4

product of zeroes =c/a

product=-1/4

aB^2+Ba^2

aB(B+a). [aB = product,B+a=a+B=sum]

-1/4×5/4

=-5/16

Answer 2

Good Morning

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Here's ur answer....

p(x) = 4x²-5x-1

Since a and b are the zeroes of p(x),

we can use the equations that

a+b = -b/a      and

ab = c/a

Hence,

a+b = -b/a

a+b = -(-5)/4 = 5/4

ab = c/a

ab = -1/4

ab² + ba² can also be written as,

ab² + ba² = ab(a+b)

Hence,

ab²+ba²

= ab(a+b)

= -1/4 * 5/4

= -5/16

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