Question

If a and B are zeros of p(x) = x2 + 5x +γ such that a-ß = 1, then find γ
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Answer 1

Polynomial Rules

• a + ß = - Coefficient of x/Coefficient of x²

• aß = Constant Term/Coefficient of x²

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Given : a - ß = 1 _(i)

• a + ß = - 5/1

• a + ß = - 5 _(ii)

By adding (i) and (ii),

• 2a = - 4

• a = - 2

By substituting value we get

• - 2 + ß = - 5

• ß = - 3

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• aß = γ/1 = γ

• - 2 × (- 3) = γ

• 6 = γ

Answer : 6

Answer 2

Hi there !!

x²+5x+y

Coefficient of x² =1

coefficient of x =5

constant term =y

a-b =1 (given) ------(1)

We know that,

a+b =-b/a = -5

a+b=-5--------(2)

From equation (1)1

a=1+b---(3)

Put a in (2)

1+b+b=-5

1+2b=-5 =>2b=-6

b=-3,Put b in equation (3)

and a = -2

a. b= c/a

y/1= -3. -2 => 6

y=6

Thank you:)