Math, asked by angad8493, 1 year ago

If a and b are zeros of p(x) = x2 + x -1 , find 1 /a+1/beta. .

Answers

Answered by VijayaLaxmiMehra1
5

Answer:-

1

Step by step explanation

Given quadratic polynomial :

p ( x ) = x^2 + x - 1

Let alpha and beta be the zeroes of the given polynomial

 \alpha  +  \beta  =  - 1 \\  \\  \alpha  \beta  =  - 1

 \frac{1}{ \alpha }  +  \frac{1}{ \beta }  \\  \\  =  >  \frac{ \beta  +  \alpha }{ \alpha  \beta }  \\  \\  =  >  \frac{ - 1}{ - 1}  \\  \\  =  >  1

Hope it helps!

Answered by Anonymous
2

Answer:

Given that

p(x) = x² + x - 1

Let alpha and beta are zeroes of the polynomial

alpha + beta = -1

alpha × beta = -1

===> 1/alpha + 1/beta

===> beta + alpha / alpha × beta

===> -1 / -1

===> 1

1/a+1 / beta = 1

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