Math, asked by sidguitarist123, 11 months ago

if a and b are zeros of polynomial Kx²+4x+4 find the value of k such that (a+b)²+2ab=24​

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Answered by ankita1351
8

Answer:

a+b=-4/k and a×b=4/k

now, (a+b)²+2ab=24

or, (-4/k)²+2×4/k=24

or, 16/k²+8/k=24

or, (16+8k)/k²=24

or, 16+8k=24k²

or, 24k²-8k-16=0

or, 8(3k²-k-2)=0

or, 3k²-k-2=0

or, 3k²-3k+2k-2=0

or, 3k(k-1)+2(k-1)=0

or, (k-1)(3k+2)=0

either, k-1=0; or, k=1

or, 3k+2=0; or, k=-2/3

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