Question

if a and b are zeros of polynomial x² - 4x -12 , find the value of a³b + ab³. *​

Answer 1

Step-by-step explanation:

$p(x) = {x}^{2} - 4x - 12 = 0\\ {x}^{2} - 6x + 2x - 12 \\ x(x - 6) + 2(x - 6) \\ (x - 6)(x + 2) \\ x = 6 \: \: \: \: \: \: x = - 2 \\ a = 6 \: \: \: \: \: \: \: \: b = - 2 \\ {6}^{3} \times ( - 2) + {( - 2)}^{3 } \times 6 \\ 216 \times ( - 2) + ( - 8) \times 6 \\ - 432 + ( - 48) \\ - 480$

i hope its helpfull