Question

if a and b are zeros of the polynomial 4x^2+3x+7 then find the value of 1/a+1/b​

Answer 1

==> In the given equation ,

p(x) = 4x² + 3x + 7

And α = alpha , β = beta are the zeroes of the given polynomial .

We have to find the value of ,

1/α + 1/β

So, lets find this,

We have the following values ,as

a = 4

b = 3

c = 7

We know that,

α + β = -b/a

= -3/4

Also we know that,

αβ = c/a

= 7/4

Now, by using the identity of quadratic expression ,[ 1/α + 1/β = α+β/αβ ]

By putting the obtained value we get,

1/α + 1/β = α+β/αβ

= -3/4/74

4 and 4 get cancelled and we get

= -3/7

Therefore 1/α + 1/β = -3/7

I hope it will helpfull...☺️

Answer 2

==> In the given equation ,

p(x) = 4x² + 3x + 7

And α = alpha , β = beta are the zeroes of the given polynomial .

We have to find the value of ,

1/α + 1/β

So, lets find this,

We have the following values ,as

a = 4

b = 3

c = 7

We know that,

α + β = -b/a

= -3/4

Also we know that,

αβ = c/a

= 7/4

Now, by using the identity of quadratic expression ,[ 1/α + 1/β = α+β/αβ ]

By putting the obtained value we get,

1/α + 1/β = α+β/αβ

= -3/4/74

4 and 4 get cancelled and we get

= -3/7

Therefore 1/α + 1/β = -3/7

Thanks !!!