if a and b are zeros of the polynomial x to the power2 -2x-15 then the polynomial whose zeros are 2a and 2b
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Solution :
Let p(x) = x² - 2x -15
On comparing with ax² + bx +C, we get
a =1,b = -2 and c = -15. ......... (1/2)
Given, a and b are the zeroes of p(x).
Sum of zeroes, (a + b) = -b/a
a + b = -2/1
a + b = 2. .........(i)
and product of zeroes, (a - b) = c/a
ab = -15/1
ab = -15. ........(ii)
We have to form a polynomial whose zeroes are 2a and 2b
Sum of zeroes = 2a +2b = 2(a +b)
= 2 x 2= 4 [using Eq. (i)]
and product of zeroes = 2a.2b
= 4ab = 4 x (-15) = -60 [using Eq. (ii)]
Required polynomial
= x² - (Sum of zeroes) x + (Product of zeroes)
= x² - 4x + (-60)
= x² - 4x-60
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