if a and B are zeros of the quadratic polynomial p(x)=x²-8x+K such that a-B=4 then the value of K is
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Answer:
a+B=-b/a=-(-8)/1=8---1
a-B=4---2
Solve 1 and 2
then a=6 B=2
aB=6(2)=12=c/a=K/1=K
HENCE K=12
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