if a and b ate two positive integers where a is greater than 0 and b is a factor of s , then HCF of s and b is a)b b) a c)3ab. d) a÷b
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GIVEN:-
- a>0
- b factor of s
HCF = highest comman factor
factor of b = 1 × b
factors of s = 1×b×K
then hcf = 1 × b = b
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Answer:
Highest not unusualplace aspect is 'b'.
option (a) is correct.
Step-by-step explanation:
Given a and b are fantastic integer
and a more than b and zero
b is a aspect of a
We ought to discover the H.C.F of (a, b)
Factors of a : 1, b, a, …
b factors : 1, b,.....
Highest not unusualplace aspect is 'b'.
option (a) is correct.
your query is incomplete, however maximum likely your complete query is:
if a and b ate fantastic integers in which a is more than zero and b is a aspect of a , then HCF of a and b is a)b b) a c)3ab d) a ÷ b
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