if a and b be two non-void sets with n elements in common then prove that a x b & b x a will have n2 elements in common.
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(AxB) ∩ (CxD) = (A∩C) x (B∩D)
So for this we will get
(AxB) ∩ (BxA) = (A∩B) x (B∩A)
n(A∩B) = n elements
n [(A∩B) x (B∩A)] = n (A∩B) . n(B∩A) = n.n = n² elements
by (i), n [(AxB) ∩ (BxA)] = n² elements
So for this A x B and Bx A have n² elements in common
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