if a and B be two zeroes of quadratic polynomial p(×)=2xsquare -3x+7, evaluate a square+b square
Answers
Answered by
2
Answer:
Step-by-step explanation:
We have, p(x) = 2x^2 - 3x + 7.
And, a and b are two zeros of the above polynomial.
Now, sum of zeros = a+ b = -B /A
So, a+b= -(-3)/2 = 3/2. { B= -3 and A = 2}
Product of the zeros= ab = C/A = 7/2. { C=7 and A = 2} ------------(I)
Now, a+b = 3/2
Squaring both the sides we get,
or, (a+b)^2 = (3/2)^2
or, a^2+b^2+2ab = 9/4
or, a^2+b^2+ 2× 7/2= 9/4 { From (I) }
or, a^2+b^2= 9/4 - 7
or,a^2+b^2= -19/4
Hence, a^2+b^2 = -19/4
MARK ME AS BRAINLIEST.
Similar questions