Math, asked by nishilalwani361, 6 months ago

if a and B be two zeroes of quadratic polynomial p(×)=2xsquare -3x+7, evaluate a square+b square

Answers

Answered by mridullaltumukherjee
2

Answer:

Step-by-step explanation:

We have, p(x) = 2x^2 - 3x + 7.

And, a and b are two zeros of the above polynomial.

Now, sum of zeros = a+ b = -B /A

So, a+b= -(-3)/2 = 3/2. { B= -3 and A = 2}

Product of the zeros= ab = C/A = 7/2. { C=7 and A = 2} ------------(I)

Now, a+b = 3/2

Squaring both the sides we get,

or, (a+b)^2 = (3/2)^2

or, a^2+b^2+2ab = 9/4

or, a^2+b^2+ 2× 7/2= 9/4 { From (I) }

or, a^2+b^2= 9/4 - 7

or,a^2+b^2= -19/4

Hence, a^2+b^2 = -19/4

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