If A and B can finish a task in 42 days provided the ratio of efficiency between A and B is 7:3, then how many days will A take to complete the task alone?
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Let A be the number of days it will take A to complete the task alone.
Then, since the ratio of efficiency of A and B is 7:3
Solution:
Let the task be considered to have
42 * 10 = 420 of work.
In one day both A and B can do = 42/10 = 4.2
In one day A can do 7 units and B can do 3 units.
The number of days required by A to complete the task alone= 420/7 = 60
Therefore, A will take 60 days to complete the task alone.
Hope this will help.
Then, since the ratio of efficiency of A and B is 7:3
Solution:
Let the task be considered to have
42 * 10 = 420 of work.
In one day both A and B can do = 42/10 = 4.2
In one day A can do 7 units and B can do 3 units.
The number of days required by A to complete the task alone= 420/7 = 60
Therefore, A will take 60 days to complete the task alone.
Hope this will help.
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