If a and b is not equal to 0 are the roots of the equation x^2 + ax + b = 0 then the least value of X^2 + ax + b (X ∈ R) is
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Answer:
-(a^2 - 4b) ÷ 4
Step-by-step explanation:
we know that least value of quadratic equation having a>0 is -D ÷ 4a
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