Math, asked by UTKARSHN6841, 11 months ago

If a and b together can complete a piece of work in 15 days and b alone in 20days. In how many days can a alone complete the work?

Answers

Answered by sunlight41
11

Step-by-step explanation:

work of a+b=1/15

work of b alone=1/20

now, work done by a =(a+b)- work of b

1/15- 1/20

=1/60

hence a do it alone in 60 days.

Answered by wifilethbridge
5

A can complete work in 60 days alone

Step-by-step explanation:

A and B complete work together in days = 15

(A+B)'s 1 day work = \frac{1}{15}

B alone can do work in days = 20

B's 1 day work =\frac{1}{20}

A's 1 day work = \frac{1}{15}-\frac{1}{20}

A's 1 day work = \frac{1}{60}

So, A can complete work in 60 days alone

#Learn more:

A and B can together finish a work in 30 days. They worked at it for 20days and then B left. The remaining work was done by A alone in 20more days. A alone can finish the work in?

https://brainly.in/question/1638030

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