Math, asked by yogeshweponx6348, 1 year ago

If A and B together can complete a piece of work in 15 days and B alone in 20 days, in how many days can A alone complete the work?
A.60
B.45
C.40
D.30

Answers

Answered by Anonymous
2
\textbf{\huge{ANSWER:}}

Given:

A and B can together can complete the work in = 15 days

B alone can complete the work in = 20 days

1 day work of A and B together = \frac{1}{15}\\ ...(1)

1 day work of B alone = \frac{1}{20}\\ ...(2)

(1) - (2)

 \frac{1}{15} - \frac{1}{20} \\ \\ = \frac{20 - 15}{300} \\ \\ = \frac{5}{300} \\ \\ = \frac{1}{60}

Therefore, 1 day work of A alone = \frac{1}{60}\\

Total number of days required by A to complete the work alone = 60 days

Thus,

\textbf{(A) 60 is the answer.}

Hope it Helps!! :)
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