Question

if a and b two digits of a number 394AB such that this number is divisible by 60 then a+b is equal to

Answer 1

Answer:

2. {Edited.}

Step-by-step explanation:

If 394AB is divisible by 60, then it must be divisible by both 6 and 10. {60 = 10 × 6.}

Clearly, B = 0, since the number is divisible by 10 only when it has 0 at unit's place.

Checking divisibility of 6, we need to check divisibility test of both 2 and 3.

Since the digit at the unit's place is even (0), it is divisible by 2, but it don't help in getting the value of A.

Checking divisibility test of 3 and taking sum of digits, we get,

3 + 9 + 4 + A + 0

→16 + A

Nearest increased multiple of 3: 18

So, we need to get the value of sum of digits 18, now we have,

16 + A = 18

{Transposing 16 to RHS...}

→A = 18 - 16

→A = 2

So, we have the values for A = 4 and B = 0.

A + B: 2 + 0

→2

Hence, the sum of A and B is 2.

{Hope it helped you...}

{Kindly Mark as Brainliest...}

{Thanks for reminding me...!}

Answer 2

AnswEr :

⍟ Given Number : 394AB

Here A and, B are Digits. This Given Number is Divisible by 60. Now we can write 60 also as (2 × 3 × 10).

• Divisibility Rule :

– If Last Digit of Number i.e. Tens Digit is Divisible by 2 or we can say it is even number then that Number is also Divisible by 2.

– If Sum of Digits of Number is Divisible by 3 then that Number is also Divisible by 3.

– If Last Digit of Number i.e. Tens Digit is 0 then that Number is Divisible by 10.

━━━━━━━━━━━━━━━━━━━━━━━━

As Number is Completely Divisible by 60 i.e. (2 × 3 × 10) then Last Digit of Number must be 0 that means B = 0

◗ Now, Sum of All Digits of Number :

↠ 394AB

↠ (3 + 9 + 4 + A + B)

• we will take value of B as 0

↠ (3 + 9 + 4 + A + 0)

↠ 16 + A

To make it Divisible by 3, we should must Add any of these one digit 2, 5 or, 8.

______________________________

• Taking A as 2 :

• Sum of Numbers will be (16 + A) = (16 + 2) = 18 i.e. Divisible by 3.
• Number Formed will be 39420 &, it's completely Divisible by 60 in 6570 times.

↠ (A + B) = (2 + 0) = 2

_________________

• Taking A as 5 :

• Sum of Numbers will be (16 + A) = (16 + 5) = 21 i.e. Divisible by 3.
• Number Formed will be 39450 &, it's completely Divisible by 60 in 6575 times.

↠ (A + B) = (5 + 0) = 5

_________________

• Taking A as 8 :

• Sum of Numbers will be (16 + A) = (16 + 8) = 24 i.e. Divisible by 3.
• Number Formed will be 39480 &, it's completely Divisible by 60 in 6580 times.

↠ (A + B) = (8 + 0) = 8

∴ Value of (a + b) can be either 2 or 5 or 8.