Question

If a and b varies inversely as each other and a = 16 when b = 4. Find b when a = 8​

Answer 1

Answer:

a varies b inversely

therefore , a=k.(1/b)

or, a=k/b

Now a=16 b=4

so 16=k/4

or, k=64

again , a=8 b=?

therefore , 8=64/y

or, 8y = 64

or, y = 8

so value of y is 8

Answer 2

Answer:

when the value of a is 8, the value of b is 8

Step-by-step explanation:

They have given that a and b are inversely proportional to each other

Therefore a ∝ (1/b).

Implies ab = k where k is proportionality constant.

For two sets of a and b values, we can write it as

             $a_{1} b_{1} =a_{2} b_{2}$

Let the value of $a_{1} =16$

Let the value of $b_{1} =4$

To find the value of b when the value of a is 8,

Consider,

                 $a_{1} b_{1} =a_{2} b_{2}\\(16)(4)=(8)b_{2} \\b_{2} =8$

Therefore the value of b is 8.