Math, asked by myadav1164, 10 months ago

If A and Bare acute angles such that tanA=1/3 ,tanB=1/2andtan (A+B)=tanA+tanB/1-tanA+tanB,show thatA+B=45

Answers

Answered by pulakmath007
1

Answer:

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Step-by-step explanation:

ANSWER ::

tan (A+B)=tanA+tanB/1-tanA×tanB

tan (A+B)= (1/2+1/3) /1- ( 1/2×1/3)

tan (A+B) = 5/6 / 1- 1/6

tan (A+B) = 5/6 / 5/6

tan (A+B) = 1

A + B = 45°

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