If A and Bare acute angles such that tanA=1/3 ,tanB=1/2andtan (A+B)=tanA+tanB/1-tanA+tanB,show thatA+B=45
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Step-by-step explanation:
ANSWER ::
tan (A+B)=tanA+tanB/1-tanA×tanB
tan (A+B)= (1/2+1/3) /1- ( 1/2×1/3)
tan (A+B) = 5/6 / 1- 1/6
tan (A+B) = 5/6 / 5/6
tan (A+B) = 1
A + B = 45°
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