Math, asked by bhardwajparveen28373, 9 months ago

If a and bare zeros of P(x)=x^2+x+1,
find the value of ab​

Answers

Answered by Anonymous
2

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Answered by swopnamaharana7
2

Answer:

Given P(x)= x² +x+1.

so to find ab=-b/a = -1/1= -1

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