Question

If a and ß be the zesoes of the polynomia 02x-5x+7, find the value of 1÷a+1÷B
find the value of 1
-
B​

Answer 1

Answer:

tnBjajaahshsgdgdgdghdshdhdhdhsh

Answer 2

Answer:

x2-5x+k

 Here, a=1, b=-5 and c=k 

Now, α+ β = -b/a= -(-5)/1= 5 

α*β  = c/a= k/7= k

 Now,α - β =1

 Squaring both sides, we get,

 (α - β)2=12 

⇒ α2 + β2 - 2αβ = 1

⇒ (α2 + β2 + 2αβ) 

please make as British answer