Question

If a and beta are the zeros of x²+5x+6 find the value of a-¹+ beta-¹ ?​

Answer 1

Answer:

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Answer 2

Answer:

Great question:-

Step-by-step explanation:

Quadratic equation

$x^{2} + 5x + 6$

From equation we have,

a = 1,   b = 5 and c = 6

sum of zeros       = α + β = $\frac{-b}{a} = \frac{-5}{1}$ = -5

product of zeros = α × β = $\frac{c}{a} = \frac{6}{1}$ = 6

now, $\alpha ^{-1} + \beta ^{-1}$

          = $\frac{1}{\alpha} + \frac{1}{\beta}$   ( negative exponents convert into positive)

          = $\frac{\alpha+\beta }{\alpha\beta}$      ( LCM or cross multiplication)

put the value of  α + β and α × β,

           = $\frac{-5}{6}$

hoping for you will get it........