if a and l be the first and last term of A.P. and S be the sum of its all terms then it's common difference is?
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Hello!
First term = a
Last term = l
Sum = S
According to Question,
S = n/2 [2a + (n - 1) d]
2S = 2an + n (n - 1) d
2S = 2an + n²d - nd
2S - 2an = d (n² - n)
Therefore, d = (2S - 2an) / n² - n
I hope it helped.
Thank You!
First term = a
Last term = l
Sum = S
According to Question,
S = n/2 [2a + (n - 1) d]
2S = 2an + n (n - 1) d
2S = 2an + n²d - nd
2S - 2an = d (n² - n)
Therefore, d = (2S - 2an) / n² - n
I hope it helped.
Thank You!
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