if a and l be the first and last term of A.P. and S be the sum of its all terms then it's common difference is?
Answers
Answered by
4
Hello!
First term = a
Last term = l
Sum = S
According to Question,
S = n/2 [2a + (n - 1) d]
2S = 2an + n (n - 1) d
2S = 2an + n²d - nd
2S - 2an = d (n² - n)
Therefore, d = (2S - 2an) / n² - n
I hope it helped.
Thank You!
First term = a
Last term = l
Sum = S
According to Question,
S = n/2 [2a + (n - 1) d]
2S = 2an + n (n - 1) d
2S = 2an + n²d - nd
2S - 2an = d (n² - n)
Therefore, d = (2S - 2an) / n² - n
I hope it helped.
Thank You!
Similar questions
Math,
8 months ago
Physics,
8 months ago
Computer Science,
1 year ago
Science,
1 year ago
World Languages,
1 year ago
English,
1 year ago