If A and Q are the only two outcomes of an event and P(Q) =0.68 then the value of P(A) would be
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A and Q are the only two outcomes so their sum is one. For example, A and Q be win and loss. Win probability be 0.32 and loss be 0.68. So, their sum is one(not relating to real figures of the question just explaining)
P(A) should be 1 - 0.68 = 0.32.
rickmorgan:
what do u think?
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