Question

if a and theta are zeros of the quadratic polynomial x2-x-6 find the value of 1÷a+1÷ theta​

Answer 1

Answer:

Answer = -1/6

Step-by-step explanation:

x² - x - 6

= x² - 3x + 2x - 6

= x (x - 3) +2 (x - 3)

= (x + 2) (x - 3 )

x = - 2 I x = 3

Now ,

a = - 2

theta = 3

1/a + 1/theta

= - 1/2 + 1/3

= - 3 + 2 /6

= -1/6

Hope it helps.