If A anf B are tow disjoint sets and n(A)=10 and n(B)=8find n (AUB)and n(AnB)
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A and B are disjoint sets so they don't have any elements common.
So,
n(A ∪ B) = n(A) + n(B)
==> n(A ∪ B) = 10 + 8
==> n(A ∪ B) = 18
Also,
==> n(A ⋂ B) = 0 ( because the sets are disjoint )
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