Math, asked by maryrosemartus195, 6 months ago

If A anf B are tow disjoint sets and n(A)=24 and n (B)=22 find n(AUB) and n(A-B)

Answers

Answered by jackie29
9

Answer:

n(AUB)=46 and n(A - B) = 24.

Step-by-step explanation:

1. n(AUB)=n(A) + n(B)

=24+22

=46.

2. n(A-B)= n(A) - n(A intersection B)

Here A intersection B is zero, because it is an disjoint set and there is no common elements in it.

n(A-B)= 24 - 0

therefore n(A-B) = 24.

I think it will be useful to you !!!

Answered by ahervandan39
1

n(AUB) = 46 \: and \: n(A-B) = 24 \\  \\ 1. \: n(AUB) = n(A) + n (B) \\  = 24 + 22 \\  = 46 \\  \\ 2. \: n(A-B) = n(A) -n \\ here \:  A \:  intersection \:  B \:  is \:  \\  zero ,  \:  \\ because  \: it \:  is \:  a \:  disjoint \:  \\   and \:  there \:  is \:  no  \:  \\ common \: elements \: in \: it \:  \\ n(A-B) = 24 - 0 \\ therefore \: n(A-B) \:  = 24</p><p>.

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