If A anf B are tow disjoint sets and n(A)=24 and n (B)=22 find n(AUB) and n(A-B)
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Answer:
n(AUB)=46 and n(A - B) = 24.
Step-by-step explanation:
1. n(AUB)=n(A) + n(B)
=24+22
=46.
2. n(A-B)= n(A) - n(A intersection B)
Here A intersection B is zero, because it is an disjoint set and there is no common elements in it.
n(A-B)= 24 - 0
therefore n(A-B) = 24.
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