Question

If a,ß are the roots of the equation 
8x ^{2} - 3x + 27 = 08x2−3x+27=0 
then the value of
( \frac{ \alpha ^{2} }{ \beta } ) ^{ \frac{1}{3} } + ( \frac{ \beta ^{2} }{ \alpha } ) {}^{ \frac{1}{3} }(βα2​)31​+(αβ2​)31​ 
is
​

Answer 1

Answer:

fuivigurrbkbjbkbjvyff