Question

If a, ß are the roots of x² + P(x+1)+c = 0 then (1+a) (1+B) =
​

Answer 1

Answer:

Step-by-step explanation:

for this question, we must know that for any polynomial

$ax^{2} +bx+c$ and the zeroes are a, ß, then

a + ß = -b/a ---------1

aß     = c/a ------------2

now for the question \

x² + P(x+1)+c = 0

x²+Px+P+c = 0

therefore we get a = 1, b=P, c=(P+c) -------------3

therefore,

for (1+a)(1+ß)= answer

1 + a + ß + aß = answer

using equation 1, 2 and 3

1 + (-P/1) + ((P+c)/1)

1 - P + P + c

1+c = answer

HOPE THIS HELPS

CHEERS MATE, PLEASE MARK BRAINLIEST

Answer 2

Answer:

hope you UNDERSTOOD this answer