Question

If a, ß are the zeroes of 2x2 + 3x +1 then a + B
*****
A-2/3
B) -3/2
C) 1/2
D)-1/2​

Answer 1

In the given p(x) = 2x² + 3x + 1

a = coefficient of x² = 2

b= coefficient of x = 3

c= constant in p(x) = 1

Thus, by equation,

$\alpha + \beta = \frac{ - b}{a} \\ = \frac{ - 3}{2}$

Thus (b) is the correct option

Answer 2

• Option b is correct answer.

Given,

$\rm{}p(x) = {2x}^{2} + 3x + 1$

We know,

By relationship of zeroes & coefficient in a polynomial,

$\text{Sum of Zeroes} = \text{-(coefficient of x)/coefficient of x²} \\ \\ \bf \text{Sum of Zeroes} = \rm{ \dfrac{ - (coefficient \: \: of \: \: x)}{coefficient \: \: of \: \: {x}^{2} } }$

Thus,

$\huge{}\alpha + \beta \: \: = \: \: \sf \red {\frac{ - 3}{2} }$