Question

If a,ß are the zeroes of the polynomial f(x)=x power 2+x+1, then (Alfa+1) (beta+1)
is equal to​

Answer 1

Answer:

m

Step-by-step explanation:

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Answer 2

Answer:

hey friend here is your answer

Step-by-step explanation:

f(x) = x² + x + 1

let p,q be roots of f(x)

(Note : replace alpha and beta with p and q respectively)

We want (p+1)(q+1) = ?

we know that p + q = sum of roots = -b/a = -1/1 = -1

pq = products of = c/a = 1/1 = 1

roots

therefore, we have p+q = -1 and pq= 1

(p+1)(q+1) = pq + p + q + 1 = 1 - 1 + 1 = 1

therefore, (p+1)(q+1) = 1

Hence your final answer is 1.

I hope you get your answer

thanks for asking

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