Question

. If a, ß are the zeroes of the polynomial p(x) = 6x2 + x - 12, then find a quadratic
polynomial whose zeros are a + 2 and ß + 2.​

Answer 1

Answer:

6x^2+23x+10

Step-by-step explanation:

6x^2+x-12=0

6x^2+9x-8x-12=0

3x(2x+3)-4(2x+3)=0

(2x+3)(3x-4)=0

which gives,x=(-3/2)and (4/3)

let a=4/3 and b=-3/2

then a+2=4/3+2=10/3

and b+2=-3/2+2=1/2

the required pollynomial can be written as x^2+{(a+2)+(b+2)}x+(a+2)(b+2)

=x^2+23/6x+10/6

=6x^2+23x+10