If a, ß are the zeroes of the polynomial
x2-3x + 16, then 2ab(a + b) is tell step by step please
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f(x)=6x2+x−2
a,b are its zero's / roots.
a+b=6−1,ab=6−2=−1/3
ba+ab=aba2+b2=ab(a+b)2−2ab
=(−1/3)(−1/6)2−2(−1/3)=−1/3361+32
=−(121+2)=12−25
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