Question

If a, ß are the zeroes of x^2 + x -2. Then find the value of (1/a-1/ß)​

Answer 1

Answer:

The value of $(\frac{1}{\alpha }-\frac{1}{\beta })$ is $\frac{1}{2}$.

Step-by-step explanation:

The sum and product of a quadratic equation ax² + bx + c = 0 are:

$\alpha +\beta =-\frac{b}{a}\\\alpha \times \beta =-\frac{c}{a}$

The quadratic equation provided is, x² + x - 2 = 0.

Compute the value of $(\frac{1}{\alpha }-\frac{1}{\beta })$ as follows:

$(\frac{1}{\alpha }-\frac{1}{\beta })=\frac{\alpha +\beta }{\alpha \times\beta }=\frac{-(1/1)}{(-2/1)}=\frac{1}{2}$

Thus, the value of $(\frac{1}{\alpha }-\frac{1}{\beta })$ is $\frac{1}{2}$.

Answer 2

Answer:

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