If a, ß
are the zeroes of x2 + 7 then a + B =
Answers
Answered by
0
Answer:
Given that,
α,β are the zeroes of the polynomial p(x)=2x
2
−7x+3
Sum of zeroes (α+β)=
a
−b
=
2
−(−7)
=
2
7
Product of zeroes αβ=
a
c
=
2
3
∴α
2
+β
2
=(α+β)
2
−2αβ
=(
2
7
)
2
−2(
2
3
)
=
4
49
−
4
12
=
4
37
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Answered by
0
Answer:
X^2 = 7
x = + or - rt7
Rt7-rt7 =0
Another method
alpha +beta = - b/a
= 0/1
= 0
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