Question

If a, ß are the zeros of polynomial f(x) = x2 - p(x + 1) - C, then (a + 1)(beta+ 1) =​

Answer 1

Answer:

f(x)=x2-px-p-c

$\alpha + \beta = \frac{ - b}{a} = \frac{ - ( - p)}{1} = p \\ \alpha \beta = \frac{c}{a} = - (p + c) \\ ( \alpha + 1)( \beta + 1) \\ = \alpha \beta + \alpha + \beta + 1 \\ = - (p + c) + p + 1 \\ = - p - c + p + 1 \\ = - c + 1$