If a, ß are the zeros of the polynomial 24²+7y+5
write the value alfa+ß+Alfa bitta
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Given polynomial 2y2 +7y+5
Here a=2,b=7,c=5
α,β are two zeroes
So, sum of the zeroes =α+β=− a b= 2 −7
Product of the zeroes =αβ= a c = 2 5
Now just put the values
α+β+αβ=(α+β)+αβ = 2 −7 + 2 5 = 2 −7+25= 2 −2 =−1
∴ So, the required answer is −1.
Step-by-step explanation:
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