Question

If a,ß are the zeros of the polynomial p(x)=x2
- px - (p + c), then (a + 1)(8 + 1) is equal to :
(a) c-1 (b) 1-C (c) c (d) 1+c
. ​

Answer 1

Answer:B

Explanation: zeros means root-

Now solving the equation:

Sum of the roots = a+ß = p  ---------------1

Product of roots = aß = -(p+c) ---------------2

solving above two euation by adding them

aß + ß + a = -c

ß(a+1) + a+1 = -c+1

(a+1)(ß+1) = -c + 1

and on taking ß is 8

(a+1)(8+1) = 1 - c

I hope this helps :)

Answer 2

If a,ß are the zeros of the polynomial p(x)=x2
- px - (p + c), then (a + 1)(8 + 1) is equal to :
(a) c-1 (b) 1-C (c) c (d) 1+c
. ​