Question

if a, ß are
the zeros of the polynomial
x^2+ 6x+2. then?
(1/a+1/B) =? (a.) 3 (b.) -3 (c.) 12 (d.) -12​

Answer 1

Answer:

1/alpha+1/beta= alpha+beta/alpha*beta

= -6/2

= -3

So, the right option is (b) -3

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Answer 2

Answer:

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