Question

if a, ß are the zeros of the polynomial X2+2x+1 ; then 1/a+1/b​

Answer 1

Answer:

1/a + 1/b = -2

Step-by-step explanation:

Given, a & b are the zeroes of x²+2x+1

» a+b = -2/1 -----(1)

» ab = 1/1 ------(2)

Now, 1/a + 1/b = (a+b)/ab

= -2/1

= -2

Therefore, 1/a + 1/b = -2

Answer 2

Answer:

this topic is from quadratic equation.

so we should know what is quadratic equation

ax²+bx+c=0

this is quadratic equation.

Step-by-step explanation:

given: they said that a and ß are the zeros of the quadratic equation.

zeros of quadratic equation is nothing but the root of the quadratic equation.

we know that

a+ß that is sum of roots is

-b/a

and product of roots is

aß = c/a

we want to find

1/a +1/b

is we solve this equation we get

a+b/ab

we will substitute the value we get

a+ß = -2/2 =-1

aß= 1/2

so

-1/ (1/2)

= -2

this is the value of

1/a+1/b = -2

HENCE this is the solution

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