If a, ß are zeroes of the quadratic polynomial ply)
B
3y2-6y+4, find the value of
+3aß .
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Step-by-step explanation:
3y2 - 6y + 4
alpha + beta = -b/a
alpha × beta = c/a
alpha + beta = 2
alpha × beta = 4/3
so value of 3 alpha × beta is
= 3 × 4/3
= 4
hence value of 3 alpha × beta is 4
hope it helps !!
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