If a, ß are zeros of x² + 5x + k, where a? +B2 =11 then k =
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since à and ß are the zeroes of given polynomial
x²+5x+k
so, à+ß=-b/a=-5/1=-5
à.ß=c/a=k/1=k
We know that
(à+ß)²=à²+ß²+2à.ß
(-5)²=11+2k
25=11+2k
2k=14
k=7
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