Math, asked by paramesh18, 11 months ago

if a/b=0.8 and 6a+11b=79, then a=?

Answers

Answered by TooFree
11

a/b = 0.8 ------------- [ 1 ]

6a + 11 b = 79 ------------- [ 2 ]


From equation [ 1 ] :

a/b = 0.8

a/b = 8/10

10a = 8b

b = 10/8 a

b = 1.25 a  ------------ Sub into equation [ 2 ]


6a + 11 b = 79

6a + 11 (1.25a) = 79

19.45 a = 79

a = 79 ÷ 19.45

a = 4


Answer: a = 4

Answered by Sidyandex
0

6a + 11 b = 79 ------------- equation [2]

From equation [ 1 ] we get :

a/b = 0.8

a/b = 8/10

10a = 8b

b = 10/8 a

b = 1.25 a  ------------ Put this into equation [ 2 ]

6a + 11 b = 79

6a + 11 (1.25a) = 79

19.45 a = 79

a = 79 ÷ 19.45


a = 4

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